NCERT Solutions Class 11 Computer Science Chapter 4 Introduction to Problem Solving

number1 = float(input("Enter the first number: "))

number2 = float(input("Enter the second number: "))

if number2 == 0:

    print("Error: Division by zero is not allowed.")

else:

    quotient = number1 / number2

    print("The quotient is:", quotient)

 

# Define the start and end values

start = 10

end = 25

for number in range(start, end + 1):

    # Check if the number is a multiple of 5

    if number % 5 == 0:

        # Print the number

        print(number)

 

Suppose we have a certain number starting from 11 to 16. The loop will be executed as follow:

seti: = 11

fori: = 11 to 16 do

print i

end loop

 

Input first number

Input second number

Input third number

Input fourth number

Set lst = [ first , second, third , fourth ]

Sort the lst

lst.sort( )

Print greatest number is lst [ -1 ]

Print smallest number is lst [ 0 ]

In programming conditionals are used for providing the condition to values, input and output. There are various conditional statements are there to evaluate the expression. Generally conditional statement give us a output in the form of true or false which is known as Boolean value.

Conditionals are required in program to check whether the value is satisfied with required output or not. 

 

def determine_winner(flips):

    player1_score = 0

    player2_score = 0

    # Process each flip

    for flip in flips:

        if flip == 1:

            player1_score += 1

        elif flip == 2:

            player2_score += 1

        

        # Check if any player has won 3 flips

        if player1_score == 3:

            return "Player 1 wins the cake!"

        elif player2_score == 3:

            return "Player 2 wins the cake!"

         return "No player won after 5 flips." #for tie conditions

result = determine_winner(flips)

print(result)

 

Step 1: Initialize total amount collected

total_amount = 0

 Step 2: Continue collecting money until the total amount is at least 200

while total_amount < 200:

 Step 3: Ask the contributor for their donation

    donation = int(input("Enter the amount donated (10, 20, or 50): "))

 Step 4: Check if the donation is valid

    if donation in [10, 20, 50]:

 Step 5: Add the donation to the total amount

        total_amount += donation

 Step 6: Print the current total amount

        print("Current total amount collected:", total_amount)

    Else:

Step 7: Inform the user about the invalid donation amount

        print("Invalid donation amount. Please enter 10, 20, or 50.")

8: Final message when the total amount reaches or exceeds 200

print("Total amount of 200 has been reached.")

 

 Step 1: Input the price of the item

    PRINT "Enter the price of the item: "

price = READ input

 Step 2: Input the quantity of the item

    PRINT "Enter the quantity of the item: "

    quantity = READ input

Step 3: Calculate the total bill before tax

    total_bill = price * quantity

Step 4: Calculate GST (5% of the total bill)

    gst = total_bill * 0.05

 Step 5: Calculate the total bill including GST

    total_bill_with_gst = total_bill + gst

Step 6: Print the total bill before tax

    PRINT "Total bill before GST: ", total_bill

Step 7: Print the GST amount

    PRINT "GST (5%): ", gst

 Step 8: Print the total bill including GST

    PRINT "Total bill including GST: ", total_bill_with_gst

 

Step 1: Read the marks for each subject

    PRINT "Enter the marks for Computer Science (out of 100): "

    computer_science_marks = READ input

    PRINT "Enter the marks for Mathematics (out of 100): "

    mathematics_marks = READ input

    PRINT "Enter the marks for Physics (out of 100): "

    physics_marks = READ input

Step 2: Calculate the aggregate marks

    aggregate_marks = computer_science_marks + mathematics_marks + physics_marks

 Step 3: Calculate the percentage of marks

    // Total maximum marks for three subjects

    total_maximum_marks = 300

    // Percentage calculation

    percentage = (aggregate_marks / total_maximum_marks) * 100

 Step 4: Print the results

    PRINT "Aggregate marks: ", aggregate_marks

    PRINT "Percentage: ", percentage

 

Step 1: Read the first number

    PRINT "Enter the first number: "

    number1 = READ input

Step 2: Read the second number

    PRINT "Enter the second number: "

    number2 = READ input

Step 3: Compare the two numbers

    IF number1 > number2 THEN

 Step 4: Print the first number as the greatest

        PRINT "The greatest number is: ", number1

    ELSE

 Step 5: Print the second number as the greatest

        PRINT "The greatest number is: ", number2

    END IF

 

Step 1: INPUT n

Step 2: IF n>5 And n<15 THEN

Step 3: PRINT “GREEN”

Step 4: ELSE IF n>15 And n<225 THEN

Step 5: PRINT “BLUE”

Step 6: ELSE IF n>25 And n<35 THEN

Step 7: PRINT “ORANGE”

Step 8: ELSE

PRINT “ALL COLOURS ARE BEAUTIFUL”

Step 9: End IF

 

Step 1: INPUT units

Setp 2: SET bill := 0

Step 3: IF units > 250 THEN

COMPUTE bill := units * 20

ELSE

IF units <= 100 THEN

COMPUTE bill := units * 5

ELSE

COMPUTE bill := 100 * 5 + (units – 100) * 10

END IF

Step 4: END IF

Step 5: COMPUTE total_Bill := bill + 75

Step 6: PRINT total_Bil

 

INPUT number

SET factorial := 1, i := 1

WHILE i<= number DO

COMPUTE factorial := factorial * i

INCREASE i by 1

END LOOP

PRINT factorial

 

1. Wake up

2. Brush our teeth

3. Do some exercise

4. Take a bath

5. Get ready

6. Take a breakfast

7. Take a lunch box

8. Go to bus stand

9. Take a bus

10. Get off the bus

11. Reach school or college

 

For given data,

5 and 9 are single digit number, so it will print “single digit”

47 and 99 are double digit number, so it will print “double digit”

100 and 200 is a three digit number, so it will print “big”

 

Correct algorithm:

Step 1: INPUT Number

Step 2: IF Number <= 9

“Single Digit”

Step 3: Else If Number <= 99

“Double Digit”

Step 4: Else

“Big”

Step 5: End IF

 

a) On what values will this algorithm fail?

This algorithm fails at value 0. Because in condition we specify “greater than equal to operator”. So it will accept zero also.

b) Can you improve the algorithm?

Correct algorithm:

INPUT Number

IF (0<Number) AND (Number <= 100)

ACCEPT

Else

REJECT