NCERT Solutions for Class 12 Maths Chapter 5: Continuity and Differentiability

Continuity and Differentiability is a fundamental chapter in the Class 12 Maths syllabus, offering a comprehensive understanding of essential calculus concepts. Chapter 5 delves into the continuity of functions, differentiability, and their applications, forming the foundation for advanced mathematical analysis. For students of Class 12, mastering this chapter is crucial for excelling in board exams and competitive tests.

Download PDF For NCERT Solutions for Maths Continuity and Differentiability

The NCERT Solutions for Class 12 Maths Chapter 5: Continuity and Differentiability are tailored to help the students master the concepts that are key to success in their classrooms. The solutions given in the PDF are developed by experts and correlate with the CBSE syllabus of 2023-2024. These solutions provide thorough explanations with a step-by-step approach to solving problems. Students can easily get a hold of the subject and learn the basics with a deeper understanding. Additionally, they can practice better, be confident, and perform well in their examinations with the support of this PDF.

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Access Answers to NCERT Solutions for Class 12 Maths Chapter 5: Continuity and Differentiability

Students can access the NCERT Solutions for Class 12 Maths Chapter 5: Continuity and Differentiability. Curated by experts according to the CBSE syllabus for 2023–2024, these step-by-step solutions make Maths much easier to understand and learn for the students. These solutions can be used in practice by students to attain skills in solving problems, reinforce important learning objectives, and be well-prepared for tests.

Continuity and Differentiability : Exercise 5.1

Question 1 :

Prove that the function f(x) = 5x – 3 is continuous at x = 0, at  x = – 3 and x = 5

 

Answer :


chapter 5-Continuity & Differentiability Exercise 5.1

 


Exercise 5.2

Question 1 :

Examine the continuity of the function f(x) = 2x2 – 1 at x = 3

 

Answer :

chapter 5-Continuity & Differentiability Exercise 5.1

Thus, f is continuous at x = 3

 


Exercise 5.3

Question 1 :

Examine the following functions for continuity.

(a) chapter 5-Continuity & Differentiability Exercise 5.1

(c) chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :

chapter 5-Continuity & Differentiability Exercise 5.1

chapter 5-Continuity & Differentiability Exercise 5.1

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at all real numbers greater than 5.

Hence, f is continuous at every real number and therefore, it is a continuous function.

 


Exercise 5.4

Question 1 :

Prove that the function f(x) = xn is continuous at x = n, where n is a positive integer.

 

Answer :

The given function is f (x) = xn

It is evident that f is defined at all positive integers, n, and its value at n is nn.

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at n, where n is a positive integer.

 


Exercise 5.5

Question 1 :

Is the function f defined by

chapter 5-Continuity & Differentiability Exercise 5.1

continuous at x = 0? At x = 1? At x = 2?

 

Answer :


The given function f is chapter 5-Continuity & Differentiability Exercise 5.1

At x = 0,

It is evident that f is defined at 0 and its value at 0 is 0.

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at x = 0

At x = 1,

f is defined at 1 and its value at 1 is 1.

The left hand limit of f at x = 1 is,

chapter 5-Continuity & Differentiability Exercise 5.1

The right hand limit of f at x = 1 is,

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is not continuous at x = 1

At x = 2,

f is defined at 2 and its value at 2 is 5.

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at x = 2

 


Exercise 5.6

Question 1 :

Find all points of discontinuity of f, where f is defined by

chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :


chapter 5-Continuity & Differentiability Exercise 5.1

It is observed that the left and right hand limit of f at x = 2 do not coincide.

Therefore, f is not continuous at x = 2

Hence, x = 2 is the only point of discontinuity of f.

 


Exercise 5.7

Question 1 :

Find all points of discontinuity of f, where f is defined by

chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :


The given function f is chapter 5-Continuity & Differentiability Exercise 5.1

The given function f is defined at all the points of the real line.

Let c be a point on the real line.

Case I:

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at all points x, such that x < −3

Case II:

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at x = −3

Case III:

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous in (−3, 3).

Case IV:

If c = 3, then the left hand limit of f at x = 3 is,

chapter 5-Continuity & Differentiability Exercise 5.1

The right hand limit of f at x = 3 is,

chapter 5-Continuity & Differentiability Exercise 5.1

It is observed that the left and right hand limit of f at x = 3 do not coincide.

Therefore, f is not continuous at x = 3

Case V:

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at all points x, such that x > 3

Hence, x = 3 is the only point of discontinuity of f.

 


Exercise 5.8

Question 1 :

Find all points of discontinuity of f, where f is defined by

chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :


chapter 5-Continuity & Differentiability Exercise 5.1

chapter 5-Continuity & Differentiability Exercise 5.1

 


Exercise 5.9

Question 1 :

Examine that sin|x| is a continuous function.

 

Answer :

Let, f(x) = sin|x|

This function f is defined for every real number and f can be written as the composition of two functions as,

f = g o h, where g (x) = |x| and h (x) = sin x

NCERT Solutions class 12 Continuity & Differentiability

It has to be proved first that g (x) = |x| and h (x) = sin x are continuous functions.

NCERT Solutions class 12 Continuity & Differentiability

Clearly, g is defined for all real numbers.

Let c be a real number.

Case I:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is continuous at all points x, such that x < 0

Case II:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is continuous at all points x, such that x > 0

Case III:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is continuous at x = 0

From the above three observations, it can be concluded that g is continuous at all points.

h (x) = sin x

It is evident that h (x) = sin x is defined for every real number.

Let c be a real number. Put x = c + k

If x → c, then k → 0

h (c) = sin c

NCERT Solutions class 12 Continuity & Differentiability

Therefore, h is a continuous function.

It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c.

Therefore, NCERT Solutions class 12 Continuity & Differentiabilityis a continuous function.

 


Question 2 :

Find all points of discontinuity of f, where f is defined by

chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :


chapter 5-Continuity & Differentiability Exercise 5.1

 


Question 3 :

Find all points of discontinuity of f, where f is defined by

chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :


chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at all points x, such that x > 1

Hence, the given function f has no point of discontinuity.

 


Question 4 :

Find all points of discontinuity of f, where f is defined by

chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :


chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at all points x, such that x > 2

Thus, the given function f is continuous at every point on the real line.

Hence, f has no point of discontinuity.

 


Question 5 :

Find all points of discontinuity of f, where f is defined by

chapter 5-Continuity & Differentiability Exercise 5.1

 

Answer :


The given function f is chapter 5-Continuity & Differentiability Exercise 5.1

The given function f is defined at all the points of the real line.

Let c be a point on the real line.

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at all points x, such that x > 1

Thus, from the above observation, it can be concluded that x = 1 is the only point of discontinuity of f.

 


Question 6 :

Is the function defined by  chapter 5-Continuity & Differentiability Exercise 5.1 a continuous function?

 

Answer :


The given function is chapter 5-Continuity & Differentiability Exercise 5.1

The given function f is defined at all the points of the real line.

Let c be a point on the real line.

Case I:

chapter 5-Continuity & Differentiability Exercise 5.1

Therefore, f is continuous at all points x, such that x > 1

Thus, from the above observation, it can be concluded that x = 1 is the only point of discontinuity of f.

 


Question 7 :

Discuss the continuity of the function f, where f is defined by

f =NCERT Solutions class 12 Continuity & Differentiability

Answer :


The given function is f = NCERT Solutions class 12 Continuity & Differentiability

The given function is defined at all points of the interval [0, 10].

Let c be a point in the interval [0, 10].

Case I:

NCERT Solutions class 12 Continuity & Differentiability

NCERT Solutions class 12 Continuity & Differentiability

Therefore, f is continuous at all points of the interval (3, 10].

Hence, f is not continuous at x = 1 and x = 3

 


Question 8 :

Discuss the continuity of the function f, where f is defined by

NCERT Solutions class 12 Continuity & Differentiability

 

Answer :


The given function is NCERT Solutions class 12 Continuity & Differentiability

The given function is defined at all points of the real line.

Let c be a point on the real line.

Case I:

NCERT Solutions class 12 Continuity & Differentiability

NCERT Solutions class 12 Continuity & Differentiability

 


Question 9 :

Discuss the continuity of the function f, where f is defined by

NCERT Solutions class 12 Continuity & Differentiability

Answer :

The given function f is NCERT Solutions class 12 Continuity & Differentiability

The given function is defined at all points of the real line.

Let c be a point on the real line.

Case I:

NCERT Solutions class 12 Continuity & Differentiability

NCERT Solutions class 12 Continuity & Differentiability

Therefore, f is continuous at all points x, such that x > 1

Thus, from the above observations, it can be concluded that f is continuous at all points of the real line.

 


Question 10 :

Find the relationship between a and b so that the function f defined by 

NCERT Solutions class 12 Continuity & Differentiability is continuous at x = 3.

 

Answer :


The given function f is NCERT Solutions class 12 Continuity & Differentiability

If f is continuous at x = 3, then

NCERT Solutions class 12 Continuity & Differentiability

 


Question 11 :

For what value of λ is the function defined by 

NCERT Solutions class 12 Continuity & Differentiability continuous at x = 0?

What about continuity at x = 1?

 

Answer :


The given function f is NCERT Solutions class 12 Continuity & Differentiability

If f is continuous at x = 0, then

NCERT Solutions class 12 Continuity & Differentiability

Therefore, for any values of λ, f is continuous at x = 1

 


Question 12 :

Show that the function defined by Chapter%205_html_m40f6c85a.gifis discontinuous at all integral point. Here [denotes the greatest integer less than or equal to x. 

 

Answer :


The given function isChapter%205_html_m40f6c85a.gif

It is evident that g is defined at all integral points.

Let n be an integer.

Then,

NCERT Solutions class 12 Continuity & Differentiability

It is observed that the left and right hand limits of f at x = n do not coincide.

Therefore, f is not continuous at x = n

Hence, g is discontinuous at all integral points.

 


Question 13 :

Is the function defined by NCERT Solutions class 12 Continuity & Differentiability/add3190.gifcontinuous at x = π ?

 

Answer :


The given function is NCERT Solutions class 12 Continuity & Differentiability/add3190.gif

It is evident that f is defined at x = π

NCERT Solutions class 12 Continuity & Differentiability

Therefore, the given function f is continuous at x = π

 


Question 14 :

Discuss the continuity of the following functions.

(a) f (x) = sin x + cos x

(b) f (x) = sin x − cos x

(c) f (x) = sin x × cos x 

 

Answer :

It is known that if g and h are two continuous functions, then

g + h, g – h and g.h  are also continuous.

It has to proved first that g (x) = sin x and h (x) = cos x are continuous functions.

Let g (x) = sin x

It is evident that g (x) = sin x is defined for every real number.

Let c be a real number. Put x = c + h

If x → c, then h → 0

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is a continuous function.

Let h (x) = cos x

It is evident that h (x) = cos x is defined for every real number.

Let c be a real number. Put x = c + h

If x → c, then h → 0

h (c) = cos c

NCERT Solutions class 12 Continuity & Differentiability

Therefore, h is a continuous function.

Therefore, it can be concluded that

(a) f (x) = g (x) + h (x) = sin x + cos x is a continuous function

(b) f (x) = g (x) − h (x) = sin x − cos x is a continuous function

(c) f (x) = g (x) × h (x) = sin x × cos x is a continuous function

 


Question 15 :

Discuss the continuity of the cosine, cosecant, secant and cotangent functions,

 

Answer :

It is known that if g and h are two continuous functions, then

It has to be proved first that g (x) = sin x and h (x) = cos x are continuous functions.

Let g (x) = sin x

It is evident that g (x) = sin x is defined for every real number.

Let c be a real number. Put x = c + h

If x → c, then h → 0

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is a continuous function.

Let h (x) = cos x

It is evident that h (x) = cos x is defined for every real number.

Let c be a real number. Put x = c + h

If x → c, then h → 0

h (c) = cos c

NCERT Solutions class 12 Continuity & Differentiability

Therefore, h (x) = cos x is continuous function.

It can be concluded that,

NCERT Solutions class 12 Continuity & Differentiability

 


Question 16 :

 Find the points of discontinuity of f, where

NCERT Solutions class 12 Continuity & Differentiability/24e9506.gif

 

Answer :


The given function f is NCERT Solutions class 12 Continuity & Differentiability/24e9506.gif

It is evident that f is defined at all points of the real line.

Let c be a real number.

Case I:

NCERT Solutions class 12 Continuity & Differentiability/f62ef9c.gif

Therefore, f is continuous at x = 0

From the above observations, it can be concluded that f is continuous at all points of the real line.

Thus, f has no point of discontinuity.

 


Question 17 :

Determine if f defined by  NCERT Solutions class 12 Continuity & Differentiability/f52e85.gif is a continuous function?

 

Answer :


The given function f is NCERT Solutions class 12 Continuity & Differentiability/f52e85.gif

It is evident that f is defined at all points of the real line.

Let c be a real number.

Case I:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, f is continuous at x = 0

From the above observations, it can be concluded that f is continuous at every point of the real line.

Thus, f is a continuous function.

 


Question 18 :

Examine the continuity of f, where f is defined by

NCERT Solutions class 12 Continuity & Differentiability

 

Answer :

The given function f is NCERT Solutions class 12 Continuity & Differentiability

It is evident that f is defined at all points of the real line.

Let c be a real number.

Case I:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, f is continuous at x = 0

From the above observations, it can be concluded that f is continuous at every point of the real line.

Thus, f is a continuous function.

 


Question 19 :

Find the values of k so that the function f is continuous at the indicated point.

NCERT Solutions class 12 Continuity & Differentiability

 

Answer :


The given function f is NCERT Solutions class 12 Continuity & Differentiability

The given function f is continuous at x = π/2 , if f is defined at x = π/2 and if the value of the f at x = π/2 equals the limit of f at x = π/2 .

It is evident that f is defined at x = π/2 and f( π/2) = 3

NCERT Solutions class 12 Continuity & Differentiability

Therefore, the required value of k is 6.

 


Question 20 :

Find the values of k so that the function f is continuous at the indicated point.

NCERT Solutions class 12 Continuity & Differentiability

 

Answer :


The given function is

NCERT Solutions class 12 Continuity & Differentiability

The given function f is continuous at x = 2, if f is defined at x = 2 and if the value of f at x = 2 equals the limit of f at x = 2

It is evident that f is defined at x = 2 and f(2) = k(2)2 = 4k

NCERT Solutions class 12 Continuity & Differentiability

Therefore, the required value of k is 3/4.

 


Question 21 :

Find the values of k so that the function f is continuous at the indicated point.

NCERT Solutions class 12 Continuity & Differentiability

 

Answer :


The given function is NCERT Solutions class 12 Continuity & Differentiability

The given function f is continuous at x = p, if f is defined at x = p and if the value of f at x = p equals the limit of f at x = p

It is evident that f is defined at x = p and f(π) = kπ + 1

NCERT Solutions class 12 Continuity & Differentiability

Therefore, the required value of k is -2/π

 


Question 22 :

Find the values of k so that the function f is continuous at the indicated point.

NCERT Solutions class 12 Continuity & Differentiability

 

Answer :


The given function f is NCERT Solutions class 12 Continuity & Differentiability

The given function f is continuous at x = 5, if f is defined at x = 5 and if the value of f at x = 5 equals the limit of f at x = 5

It is evident that f is defined at x = 5 and f(5) = kx + 1 = 5k + 1

NCERT Solutions class 12 Continuity & Differentiability

Therefore, the required value of k is 9/5

 


Question 23 :

Show that the function defined by f(x) = |cos x| is a continuous function.

 

Answer :

The given function is f(x) = |cos x|

This function f is defined for every real number and f can be written as the composition of two functions as,

f = g o h, where g(x) = |x| and h(x) = cos x

NCERT Solutions class 12 Continuity & Differentiability

It has to be first proved that g(x) = |x| and h(x) = cos x are continuous functions.

NCERT Solutions class 12 Continuity & Differentiability

Clearly, g is defined for all real numbers.

Let c be a real number.

Case I:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is continuous at all points x, such that x < 0

Case II:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is continuous at all points x, such that x > 0

Case III:

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g is continuous at x = 0

From the above three observations, it can be concluded that g is continuous at all points.

h (x) = cos x

It is evident that h (x) = cos x is defined for every real number.

Let c be a real number. Put x = c + h

If x → c, then h → 0

h (c) = cos c

NCERT Solutions class 12 Continuity & Differentiability

Therefore, h (x) = cos x is a continuous function.

It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c.

Therefore, NCERT Solutions class 12 Continuity & Differentiabilityis a continuous function.

 


Question 24 :

Find the values of a and b such that the function defined by

NCERT Solutions class 12 Continuity & Differentiability is a continuous function. 

 

Answer :


The given function f is NCERT Solutions class 12 Continuity & Differentiability

It is evident that the given function f is defined at all points of the real line.

If f is a continuous function, then f is continuous at all real numbers.

In particular, f is continuous at x = 2 and x = 10

Since f is continuous at x = 2, we obtain

NCERT Solutions class 12 Continuity & Differentiability

Therefore, the values of a and b for which f is a continuous function are 2 and 1 respectively.

 


Question 25 :

Show that the function defined by f (x) = cos (x2) is a continuous function.

 

Answer :

The given function is f (x) = cos (x2)

This function f is defined for every real number and f can be written as the composition of two functions as,

f = g o h, where g (x) = cos x and h (x) = x2

NCERT Solutions class 12 Continuity & Differentiability

It has to be first proved that g (x) = cos x and h (x) = x2 are continuous functions.

It is evident that g is defined for every real number.

Let c be a real number.

Then, g (c) = cos c

NCERT Solutions class 12 Continuity & Differentiability

Therefore, g (x) = cos x is continuous function.

h (x) = x2

Clearly, h is defined for every real number.

Let k be a real number, then h (k) = k2

NCERT Solutions class 12 Continuity & Differentiability/29f05e7.gif

Therefore, h is a continuous function.

It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c.

Therefore, h is a continuous function.

 


Question 26 :

Find all the points of discontinuity of f defined by f(x) = |x| – |x + 1|.

 

Answer :

The given function is f(x) = |x| – |x + 1|

The two functions, g and h, are defined as

NCERT Solutions class 12 Continuity & Differentiability

NCERT Solutions class 12 Continuity & Differentiability

Therefore, h is continuous at x = −1

From the above three observations, it can be concluded that h is continuous at all points of the real line.

g and h are continuous functions. Therefore, f = g − h is also a continuous function.

Therefore, f has no point of discontinuity.

 


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